Monday, November 7, 2011

Can you help with this Geometry with Problem(45-45-90 triangle)?

so one leg is 7* sqrt(72). so the hypotenuse is sqrt(2) longer than each leg. So multiply 7*sqrt(72) by sqrt(2) so it would be 7* sqrt(72*2) = 7 * 2 sqrt(36) = 7 * 2 * 6 = 14 *6 = 84

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